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    You are at:Home»Technology»Reverse math shows why hard problems are hard
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    Reverse math shows why hard problems are hard

    TechAiVerseBy TechAiVerseDecember 2, 2025No Comments5 Mins Read2 Views
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    Reverse math shows why hard problems are hard

    When it comes to hard problems, computer scientists seem to be stuck. Consider, for example, the notorious problem of finding the shortest round-trip route that passes through every city on a map exactly once. All known methods for solving this “traveling salesperson problem” are painfully slow on maps with many cities, and researchers suspect there’s no way to do better. But nobody knows how to prove it.

    For over 50 years, researchers in the field of computational complexity theory have sought to turn intuitive statements like “the traveling salesperson problem is hard” into ironclad mathematical theorems, without much success. Increasingly, they’re also seeking rigorous answers to a related and more nebulous question: Why haven’t their proofs succeeded?

    This work, which treats the process of mathematical proof as an object of mathematical analysis, is part of a famously intimidating field called metamathematics. Metamathematicians often scrutinize the basic assumptions, or axioms, that serve as the starting points for all proofs. They change the axioms they start with, then explore how the changes affect which theorems they can prove. When researchers use metamathematics to study complexity theory, they try to map out what different sets of axioms can and can’t prove about computational difficulty. Doing so, they hope, will help them understand why they’ve come up short in their efforts to prove that problems are hard.

    In a paper published last year, three researchers took a new approach to this challenge. They inverted the formula that mathematicians have used for millennia: Instead of starting with a standard set of axioms and proving a theorem, they swapped in a theorem for one of the axioms and then proved that axiom. They used this approach, called reverse mathematics, to prove that many distinct theorems in complexity theory are actually exactly equivalent.

    “I was surprised that they were able to get this much done,” said Marco Carmosino, a complexity theorist at IBM. “People are going to look at this and they’re going to say, ‘This is what got me into metamathematics.’”

    Pigeon Proofs

    The story of the reverse-mathematics paper began in the summer of 2022, when Lijie Chen, a complexity theorist now at the University of California, Berkeley, was wrapping up his doctorate. He found himself with a lot of extra time on his hands and decided to devote a few months to reading up on metamathematics.

    “Because I was graduating, I didn’t have much research to do,” Chen said. “I was figuring I should learn something new.”

    As he read, Chen began thinking about a branch of complexity theory called communication complexity, which studies the information two or more people must exchange to accomplish certain tasks. One of the simplest problems in communication complexity, called the “equality problem,” is like a collaborative game. Two players start with separate strings of 0s and 1s (or bits). Their goal is to use as little communication as possible to determine whether their strings are the same. The simplest strategy is for one player to just send their full string for the other to check. Is there any way to do better?

    Complexity theorists proved decades ago that the answer is no. To solve the equality problem, the players need to send, at a minimum, a number of bits equal to the number in the full string. Theorists say that this string length is a “lower bound” on the amount of communication needed.

    Chen wasn’t focused on the equality problem’s lower bound itself — he was interested in how researchers had proved it. All known proofs depend on a simple theorem called the pigeonhole principle, which states that if you put some number of pigeons into a smaller number of holes, at least one hole must end up holding more than one bird. That may sound self-evident, but it can be a surprisingly powerful tool in complexity theory and beyond.

    Chen had hit upon a tantalizing hint that the link between the equality problem and the pigeonhole principle might also go the other way. It’s easy to use the pigeonhole principle to prove the equality problem’s lower bound. Could you instead use the lower bound to prove the pigeonhole principle?

    Uncanny Equality

    Chen discussed his idea with Jiatu Li, at the time an undergraduate at Tsinghua University with whom Chen had recently collaborated on another paper. To make the connection rigorous, they would have to choose a set of axioms to work with. Metamathematics researchers prefer to use axioms that are more restricted than the typical ones. These weaker axioms make it easier to pin down the precise relationships between different theorems. Chen and Li decided to work with a popular set of axioms called PV1. PV1 is strong enough to prove some important theorems about computational complexity on its own. Add a specific version of the pigeonhole principle as an extra axiom, and you can also prove the equality problem’s lower bound. In December 2022, Li and Chen formally showed that, as Chen had suspected, the proof also works with the two theorems interchanged.

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    Jonathan is a tech enthusiast and the mind behind Tech AI Verse. With a passion for artificial intelligence, consumer tech, and emerging innovations, he deliver clear, insightful content to keep readers informed. From cutting-edge gadgets to AI advancements and cryptocurrency trends, Jonathan breaks down complex topics to make technology accessible to all.

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